Types of Friction:
|

Maximum Skating Force With Constant Skate Angle
Now I will look at how the maximum skating force would be achieved. The figure below illustrates classic skating style and shows a stroke with constant blade angle. Here the parameter "Angle" is measured relative to the direction the skater is moving (not the direction an individual skate moves).
Now if we include the coefficient of friction, u_s and assume the stroke is sideways then this produces a maximum forward force Ff~0.5*u_s*M*g at an Angle~45 degrees. The maximum acceleration is a = Ff/M ~ 0.5*u_s*g . The skater's acceleration is proportional to the gravitational acceleration (g) and increases with a larger static coefficient of friction (u_s) but is formally independent of his mass. The good news is that this acceleration can be realized on the start but the bad news is that it is not maintainable at higher speed. And why not?
To find the answer let's write the power in a form you may not recognize. It can be shown that the scalar power (P) in terms of vector Force (F) and vector velocity (v) is:
P = F.v or F = P/v
Consequently, since the skater is power-limited, the force which he is able to exert decreases linearly with velocity. And at fairly high speed it means that
sin(Angle)~1/v
so the Angle decreases rapidly with increasing speed and can drop down to 5 degrees or so. This produces a much smaller forward force than the maximum. Some have interpreted this weak forward force with some inefficiency of the skating process. In fact it simply follows from the skater's limited power output. If his power were unlimited he could still skate at the maximum force but at a greatly increased stroke rate.
Shortcomings of the Fixed-Angle Stroke
It has been noticed before that stroking sideways with a large force produces a small forward force at high speed. So skating has been referred to as an inefficient force converter (sideways to forward). But it seems not to have been noticed that the small forward force acts over a long distance (at high speed) whereas the sideways force acts over a small distance -- the stroke length. In fact, in the absence of various real drags like air etc., the forward energy (force times distance) exactly equals the sideways value. At first blush it seems like we have found the perfect force converter. In fact, the sideways power does equal the forward power in the ideal case. However, the total power provided was the sideways power plus the forward power so that the sideways constant angle stroke has actually acted as a power splitter which split the skater's power into two equal pieces -- only one of which is really useful. From another point of view, if you had really converted all your input power into forward motion the sideways motion of the leg and skate would stop at the end of the stroke. There would be no energy left in the sideways motion. The existence of "toe-flicking" etc. need not be the cause of skating inefficiency but may only be the symptom showing that the constant angle stroke is inefficient. In what follows I get away from constant angle skating to see if some of the power inefficiency can be remedied.
Because of the added complexities of this section, a fully quantitative presentation is not now available. However, the topic is of such importance that I think a qualitative discussion which points to elements of the answer will be useful. The maximum force (fixed blade angle) case suffers from the fact that accelerating the skate (and skater) forward also results in an acceleration (of the leg and skate) sideways. The sideways energy does not seem recoverable at constant blade angle and represents an energy loss to the skater. So a strategy to deal with this loss to achieve high power efficiency are presented next.
In order to minimize the residual sideways energy:
I think the constant angle stroke can be used over 70-80% of the stroke length. However, towards the end of the stroke the sideways energy must be channeled forward or the inefficiency remains. This can be accomplished by turning the skate forward toward the end of the stroke (not slid-- turned). This would rely on the fact that as you lay the skate on edge it acts less like "a skate" with its power splitter properties and more like "a collection of wheels". The force equation used in the constant blade angle analysis earlier assumed that the skate acted like "a skate". That is, the wheel grip patches would be directly below the axles so there would only be a force division and not a production of torsional stresses and torques. A movement of the grip patches from below the axles would invalidate the force analysis used earlier. From my analysis of turning it became clear that when the skate turns on edge the grip patches move ahead of the axle so the properties of individual wheels become important and the velocity vector is turned. This would appear as a conversion of sideways energy to forward energy.
